Here, I explained how we can utilize the operator ellipsis (…) to pass variable number of arguments to a function. I have utilised there the concept of pointers to access the variable arguments. The standard C Library provides support to access these arguments. Use for this support
All you need is to know the last argument before the ellipsis operator(At least one argument is must to use variable arguments), let’s call it larg
suppose
fun(type var1,type var2,...)
is a function, then larg corresponds to var2
Now we need to declare the list using va_list
i.e.,
va_list al
now initialize it using va_start
va_start(al,larg);
Now to access each argument, we must know the expected type of the argument
type var_name = va_arg(al,type);
When we have accessed all the variable arguments, we need to clean up
va_end(al);
Using standard library, we can easily access the variable arguments
Take a simple example
#include <stdarg.h>
int print(int num_count,...)
/*num_count contains the number of integers passed*/
{
int i;
va_list al;
va_start(al,num_count);
for(i=1;i<=num_count;i++){
int val=va_arg(al,int);
printf("%d ",val);
}
}
int print_str(const char *str,...)
/*str has the number of strings passed*/
{
int i;
va_list al;
int num_count=atoi(str);
va_start(al,str);
int *num=&num_count;
for(i=1;i<=num_count;i++){
char *str=va_arg(al,char *);
printf("%s ",str);
}
}
int main()
{
print(3,2,3,4);
print_str("3","Hi","All","!!!");
}
OUTPUT
2 3 4 Hi All !!!
